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5/3x^2=15
We move all terms to the left:
5/3x^2-(15)=0
Domain of the equation: 3x^2!=0We multiply all the terms by the denominator
x^2!=0/3
x^2!=√0
x!=0
x∈R
-15*3x^2+5=0
Wy multiply elements
-45x^2+5=0
a = -45; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-45)·5
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*-45}=\frac{-30}{-90} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*-45}=\frac{30}{-90} =-1/3 $
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